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參考自 https://stackoverflow.com/questions/3885817/how-do-i-check-that-a-number-is-float-or-integer/20779354

--

check for a remainder when dividing by 1:

 

function isInt(n) {
   return n % 1 === 0;
}

 

If you don't know that the argument is a number you need two tests:

 

function isInt(n){
    return Number(n) === n && n % 1 === 0;
}

function isFloat(n){
    return Number(n) === n && n % 1 !== 0;
}

 

Update 2019 5 years after this answer was written, a solution was standardized in ECMA Script 2015. That solution is covered in this answer.

There is a method called Number.isInteger() which is currently implemented in everything but IE. MDN also provides a polyfill for other browsers:

Number.isInteger = Number.isInteger || function(value) {
  return typeof value === 'number' && 
    isFinite(value) && 
    Math.floor(value) === value;
};

However, for most uses cases, you are better off using Number.isSafeInteger which also checks if the value is so high/low that any decimal places would have been lost anyway. MDN has a polyfil for this as well. (You also need the isInteger pollyfill above.)

if (!Number.MAX_SAFE_INTEGER) {
    Number.MAX_SAFE_INTEGER = 9007199254740991; // Math.pow(2, 53) - 1;
}
Number.isSafeInteger = Number.isSafeInteger || function (value) {
   return Number.isInteger(value) && Math.abs(value) <= Number.MAX_SAFE_INTEGER;
};

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